1912 eighth grade exam: Could you make it to high school in 1912?

A 1912 eighth-grade exam was donated to a museum in Bullitt County, Ky.

Have a look at the questions and answers and ask yourself: Would you have made it into high school in 1912?

3. A school enrolled 120 pupils and the number of boys was two-thirds of the number of girls. How many of each sex were enrolled?

The number of boys equals 2/3 of the number of girls. Algebraically, this can be expressed as B = (2/3)G. We also know that B + G = 120. This can be expressed as (2/3)G + G = 120. So G = 72 and therefore B = 48.

The number of boys equals 2/3 of the number of girls. Algebraically, this can be expressed as B = (2/3)G. We also know that B + G = 120. This can be expressed as (2/3)G + G = 120. So G = 72 and therefore B = 48.

The number of boys equals 2/3 of the number of girls. Algebraically, this can be expressed as B = (2/3)G. We also know that B + G = 120. This can be expressed as (2/3)G + G = 120. So G = 72 and therefore B = 48.

The number of boys equals 2/3 of the number of girls. Algebraically, this can be expressed as B = (2/3)G. We also know that B + G = 120. This can be expressed as (2/3)G + G = 120. So G = 72 and therefore B = 48.

Snapshot via bullittcountyhistory.com
(Read caption)

80 girls, 40 boys

 

72 girls, 48 boys

 

75 girls, 45 boys

 

68 girls, 52 boys

 
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